PROBLEM SET 2 ANSWERS 1. a. -7    b. +2   c.  +4   d.  +3   e. -1   2.  Na2Ca2B10O18.16H2O  <  Na2O + 2CaO + 5B2O3 + 16H2O   and factoring the left side by 2 =      NaCaB5O9. 8H2O    next assigning the (OH)x and yH2O, accordingly =      NaCaB5O8(OH)2. 7H2O      NaCaB5O7(OH)4. 6H2O     NaCaB5O6(OH)6. 5H2O   answer based on 6:5 (OH)x:yH2O as problem defines   3.  Cu3SO4(OH)4 > 3CuO + SO3 + 2H2O       CuO = (239/353) x 100 = 67.3%: SO3 = (80/353) x 100 = 22.5%:  H2O = (36/353) x100 = 10.2%   4.  MgO = (31.7/40) = (0.7925/0.266) = 3      SiO2 = (63.5/60) = (1.058/0.266) = 4        Mg3Si4O11.H2O <  3MgO + 4SiO2 + 1H2O      H2O = (4.8/18) = (0.2666/0.266) = 1   5. a. minus1/2a: 4b: 1c      b. (minus8, 1, 4)   6  a.  (minus3, 2, 2)    b.  (2, minus4, 0)  c. (1, 24, minus2)   7. SG = (4 x100 / 6.02 x 1023  x 22.69 x10-23) = 2.93   8. a  1.  6       2.  24     3.  12    4.  12     b. Cu = 12,  S = 4,  H = 16,  O = 32     c. 1. Potash   2. Soda   3. Lime     d.  1. Primitive   2. C faced centered    3.  Body Centered (I)     e.  1. prismatic   2. ditetragonal dipyramidal   3.  trigonal scalenohedral    4. hexoctahedral