| Answers to Problem Set 7 | |
| 1. a. Be =Y; 3 = n; Al =Y; 2 = n; Si = Z; 6 = p; 18 = q | |
| b. Ca = X; Al = Y; 2(Al) = n; Si = Z; 2(Si) = p; 7(O) = q; (OH) = w; 2(OH) = r | |
| 2. | |
| 1 d | |
| 2 f | |
| 3 f | |
| 4 b | |
| 5 g | |
| 6 e | |
| 7 a | |
| 8 d | |
| 3. | |
| 1 g | |
| 2 f | |
| 3 e | |
| 4 d | |
| 5 a | |
| 6 g | |
| 4. | |
| 1 b | |
| 2 c | |
| 3 d | |
| 4 d | |
| 5 | 6. if both of the Z tetrahedra have a Si, then the |
| a zeolites | ev. = 1 and no other polyhedra can attach to the |
| b garnets | O. However, if at least one of the 2 Z tetrahedra are |
| c labradorite | Al, then the ev = 3/4 and more polyhedra can share |
| d sorosilicates | on that O-----prove this by Pauling's rule # 2 |
| e pyroxenes | |
| f emerald | |
| g hornblende | |
| h rubellite | |