PROBLEM SET 2 ANSWERS |
1. a. -7 b. +2 c. +4 d. +3 e. -1
2. Na2Ca2B10O18.16H2O < Na2O + 2CaO + 5B2O3 + 16H2O and factoring the left side by 2 = NaCaB5O9. 8H2O next assigning the (OH)x and yH2O, accordingly = NaCaB5O8(OH)2. 7H2O NaCaB5O7(OH)4. 6H2O NaCaB5O6(OH)6. 5H2O answer based on 6:5 (OH)x:yH2O as problem defines
3. Cu3SO4(OH)4 > 3CuO + SO3 + 2H2O CuO = (239/353) x 100 = 67.3%: SO3 = (80/353) x 100 = 22.5%: H2O = (36/353) x100 = 10.2%
4. MgO = (31.7/40) = (0.7925/0.266) = 3 SiO2 = (63.5/60) = (1.058/0.266) = 4 Mg3Si4O11.H2O < 3MgO + 4SiO2 + 1H2O H2O = (4.8/18) = (0.2666/0.266) = 1
5. a. minus1/2a: 4b: 1c b. (minus8, 1, 4)
6 a. (minus3, 2, 2) b. (2, minus4, 0) c. (1, 24, minus2)
7. SG = (4 x100 / 6.02 x 1023 x 22.69 x10-23) = 2.93
8. a 1. 6 2. 24 3. 12 4. 12 b. Cu = 12, S = 4, H = 16, O = 32 c. 1. Potash 2. Soda 3. Lime d. 1. Primitive 2. C faced centered 3. Body Centered (I) e. 1. prismatic 2. ditetragonal dipyramidal 3. trigonal scalenohedral 4. hexoctahedral
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