|
Well, Devin and I stuck around after lab and ran this
sucker again. The results are puzzling, at best. (Actually
puzzling usually is best because it means you might actually learn
something if you figure it out!)
As you recall, we expected to see color develop (and absorbance
increase) over time, because catechol (the reactant) would convert to
benzoquinone (the product), which should absorb light at 470 nm.
This reaction is catalyzed by catechol oxidase, an enzyme present in
potato extract.
We expected the product to develop faster at higher temperature, up to
a point. Above some optimal temperature, the rate should decrease as
the enzyme is distorted or denatured by heat.
Methods The enzyme solution was approximately
20 grams of potato in 5 L of water (0.4%). The substrate solution
was 1% catechol in water. We set out to measure the rate of the
reaction (V) as a function of temperature. We prepared 3
solutions in spectrophotometer cuvettes:
1. Reaction mixture (prepared for each temperature): 3 ml of enzyme
solution and 3 ml of substrate solution. (You should calculate the
concentration of potato and substrate in the reaction
mixture). 2. Control 1: 3 ml enzyme and 3 ml water (no
substrate). 3. Control 2: 3 ml substrate and 3 ml water (no enzyme). The
tests were run at 4 temperatures; 4C (ice bath), 27C (room temp), 40C
(water bath), and 80C (watrer bath). The solutions were placed at
the test temperature for 5 minutes before mixing the enzyme and substrate,
and were kept at the test temperatures when not making readings in the
spectrophotometer. The controls were kept at room temperature (this
was a short-cut- we really should have had controls at each temperature). Optical
absorbance at 470 nm was measured using a Spectronic 20. Absorbance
was read just after mixing the enzyme and substrate (time zero) and at 5
minute intervals thereafter. |